x^2dy=(xy+y^2)dx

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Solution for x^2dy=(xy+y^2)dx equation:


Simplifying
x2dy = (xy + y2) * dx

Reorder the terms for easier multiplication:
dx2y = dx(xy + y2)
dx2y = (xy * dx + y2 * dx)

Reorder the terms:
dx2y = (dxy2 + dx2y)
dx2y = (dxy2 + dx2y)

Add '-1dx2y' to each side of the equation.
dx2y + -1dx2y = dxy2 + dx2y + -1dx2y

Combine like terms: dx2y + -1dx2y = 0
0 = dxy2 + dx2y + -1dx2y

Combine like terms: dx2y + -1dx2y = 0
0 = dxy2 + 0
0 = dxy2

Solving
0 = dxy2

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-1dxy2' to each side of the equation.
0 + -1dxy2 = dxy2 + -1dxy2
Remove the zero:
-1dxy2 = dxy2 + -1dxy2

Combine like terms: dxy2 + -1dxy2 = 0
-1dxy2 = 0

Divide each side by '-1'.
dxy2 = 0

Simplifying
dxy2 = 0

The solution to this equation could not be determined.

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